A ball is thrown from the top of a tower with an initial velocity of 10 m//s at an angle of `30^(@)`above the horizontal. It hits the ground at a distance of 17.3 m from the base of the tower. The height of the tower `(g=10m//s^(2))` will be

A ball is thrown from the top of tower with an initial velocity of 10ms^(-1) at an angle of 30^(@) with the horizontal. If it hits the ground of a distance of 17.3m from the back of the tower, the height of the tower is (Take g=10ms^(-2))

A ball is thrown from the top of a tower with an intial velocity of 10 m//s at an angle 37^(@) above the horizontal, hits the ground at a distance 16 m from the base of tower. Calculate height of tower. [g=10 m//s^(2)]

A ball is thrown from the top of a tower with an intial velocity of 10 m//s at an angle 37^(@) above the horizontal, hits the ground at a distance 16 m from the base of tower. Calculate height of tower. [g=10 m//s^(2)]

A ball is thrown from the top of 36m high tower with velocity 5m//ss at an angle 37^(@) above the horizontal as shown. Its horizontal distance on the ground is closest to [ g=10m//s^(2) :

A ball is thrown from the top of 36m high tower with velocity 5m//ss at an angle 37^(@) above the horizontal as shown. Its horizontal distance on the ground is closest to [ g=10m//s^(2) :

A ball is thrown from the top of 36m high tower with velocity 5m//ss at an angle 37^(@) above the horizontal as shown. Its horizontal distance on the ground is closest to [ g=10m//s^(2) :

A stone is thrown up from the top of a tower 20,m with a velocity of 24m/s a tan elevation of 30^(@) above the horizontal. Find the horizontal distance from the foot of the tower to the point at which the stone hits the ground. Take g = 10 m//s^(2)

A ball is thrown from the top of a tower of 61 m high with a velocity 24.4 ms^(-1) at an elevation of 30^(@) above the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground?