The equations of the perpendicular bisectors of the sides `A Ba n dA C` of triangle `A B C` are `x-y+5=0` and `x+2y=0` , respectively. If the point `A` is `(1,-2)` , then find the equation of the line `B Cdot`

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

The equations of the perpendicular bisectors of the sides AB and AC of a triangle ABC are x -y+5=0 and x+2y=0 respectively . If the point A is (1,-2) , find the equation of the line BC.

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

The equations of the perpendicular bisector of the sides AB and perpendicular bisector of the sides AB and AC of a /_ABC are x-y+5=0 and x+2y=0 respectively,if the point Ais (1,-2), then the equation ofthe line BC is

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc