" 37.The distance between the line "r=2i-2j+3k+lambda(i-j+4k)" and the pla "

The distance between the line vec r=2i-2j+3k+lambda(i-j+4k) and the plane vec r*(i+5j+k)=5 is

The distance between the line vec r = 2i+2j+3k + lambda (i-j+4k) and the plane vec r . (i+5j+k) = 5 is

Find the distance between the line barr=i+j+lambda(2i+j+4k) and the plane barr.(-2i+k)=5 .

Find the shortest distance between the lines barr=(2i-j-k)+lambda(3i-5j+2k) and barr=(i+2j+k)+mu(i-j+k)

The angle between the line r = (i + 2j + 3k) + lambda (2i + 3j + 4k) and the plane r.(i + 2j -2k) = 0 is a) 0^(@) b) 60^(@) c) 30^(@) d) 90^(@)

Find the shortest distance between the lines barr=i+2j+3k+lambda(i+j+k) and barr=i+j+k+mu(i+j+k)