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The radius of the circle which has norma...

The radius of the circle which has normals `xy-2x-y+2= 0` and a tangent `3x+4y-6= 0` is

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The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The equation of the circle which has normals x-1).(y-2)=0 and a tangent 3x+4y=6 is x^2+y^2-2x-4y+4=0 x^2+y^2-2x-4y+5=0 x^2+y^2=5 (x-3)^2+(y-4)^2=5

The equation of the circle which has normals x-1)*(y-2)=0 and a tangent 3x+4y=6 is x^(2)+y^(2)-2x-4y+4=0x^(2)+y^(2)-2x-4y+5=0x^(2)+y^(2)=5(x-3)^(2)+(y-4)^(2)=5

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The equation of the circle which has a radius 5 and tangent as the line 3x-4y+5=0 at (1,2) is

The radius of the circle having the lines 3x - 4y + 4 = 0 and 6x - 8y - 7 = 0 as tangents is :

The equation of a circle which has a tangent 3x + 4y = 6 and two normals given by (x - 1)(y-2) = 0 is :

The equation of a circle which has a tangent 3x + 4y = 6 and two normals given by (x-1) (y-2) = 0 is

The equation of a circle which has a tangent 3x+4y=6 and two normals given by (x-1)(y-2)=0 is