w(2m+5)/(3)=3m-10

Solve the following eqations.Check your result in each case (2m+5)=3m-10

(2m^(2)-3m+10)-:(m-5)

If m is a real number such that m^(2)+1=3m the value of (2m^(5)-5m^(4)+2m^(3)-8m^(2))/(1+m^(2))

Suggest a distance corresponding to each of the following order of length : (i) 10^7m (ii) 10^4m (iii) 10^3m (iv) 10^2m (v) 10^(-3)m (vi) 10^(-6)m (vii) 10^(-14)m

If m=2 find the value of : (i) m-2 (ii) 3m-5 (iii) 9-5m (iv) 3m^2-2m-7

If m=2 find the value of : (i) m-2 (ii) 3m-5 (iii) 9-5m (iv) 3m^2-2m-7

A beam is supported at the two ends and is uniformly loaded.The bending moment M at a distance x from one end is given by M=(WL)/(2)x-(W)/(2)x^(2)M=(Wx)/(3)-(W)/(3)(x^(3))/(L^(2)) Find the point at which M is maximum in each case.

Find m , if (3/7)^9 / (3/7)^5 = (3/7)^((3m + 2)/(m - 2))