A point charge `Q` is kept at point `'A'` the flux through the inclined surface of cone is `(3Q)/(5epsilon_(0))`. Now another charge `-Q` is also placed at point `B`. If net flux through the inclined surface `(nQ)/(5epsilon_(0))` is Find `n`.

If the charge is placed at the center of one side, flux through the cube is (q)/(n epsilon_(0)) where .n. is

If the charger is placed at the centre of one side, flux through the cube is (q)/(n epsilon_(0)) where .n. is

A point charge .Q. is placed at a point inside the cone as shown. The flux due to the charge through the curved surface is given as (2 Q)/(3 epsilon_(0)) . Now another charge .Q. is placed vertically above at the same distance from the base. The flux through the curved surface due to both charges is .

A point charge Q is placed at the corner of a square of side a. Find the flux through the square.

A point charge Q is placed at the corner of a square of side a. Find the flux through the square.

A point charge Q is placed at the corner of a square of side a, then find the flux through the square.

A charge q is placed at point D of the cube. Find the electric flux passing through the EFGH and face AEHD .

If a point charge q is placed at the centre of a cube, then find out flux through any one face of cube.