" Infigure,"/_ACB-40" .Find "/_OAB" ."

O is the center of circle,/_ACB=40^(@) Find /_OAB

In the adjoining figure, O is the centre of the circle. AB is an arc of the circle and /_AOB=80^(@) . Find /_ACB .

In Figure,/_BCD=/_ADC and /_ACB=/_BDA. Prove that AD=BC and /_A=/_B

In Figure,/_BCD=/_ADC and /_ACB=/_BDA Prove that AD=BC and /_A=/_B

ABCD is a rhombus.If /_ACB=40^(@), find /_ADB.

ABCD is a rhombus such that angle ACB=40^(@). " Find " angle ADB.

PA and PB are tangents to the circle with center O such that /_APB=50° , find /_OAB .

PA and PB are tangents to the circle with centre O such that /_APB = 60° , find /_OAB .

In the given figure DeltaODC ~ DeltaOBA, /_BOC= 125^(@)" and "/_CDO= 70^(@) . Find /_DOC, /_DCO" and "/_OAB .

In Figure,O is the centre of the circle.If /_APB=50^(@), find /_AOB and /_OAB