Find x and y if: ` (3/sqrt(5) x-5)+i2 sqrt (5) y= sqrt(2) `

Find x and y if: ((3)/(sqrt(5))x-5)+i2sqrt(5)y=sqrt(2)

((3)/(sqrt(5))x-5)+i2sqrt(5)y=sqrt(2)

Find the values of x and y if : (3/sqrt5 x-5)+2 sqrt5 yi= sqrt2 .

If x and y are rational and if x (3 + 2 sqrt2) - y sqrt2 = y(5 -3 sqrt2) + 7(2 + x sqrt2) , then find the value of x and y

sqrt(2)x + sqrt(3)y=0 sqrt(5)x - sqrt(2)y=0

find x and y 3/sqrt(x)+1/sqrt(x)=sqrt(x) y^2-(7)^(5/2)/sqrt(y)=0

The equaiton of the line which bisects the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 (A) (4-sqrt(5))x-(3-2(sqrt(5)) y+ (2-4sqrt(5))=0 (B) (3-2sqrt(5)) x- (4-sqrt(5))y+ (2+4(sqrt(5))=0 (C) (4+sqrt(5)x-(3+2(sqrt(5))y+ (2+4(sqrt(5))=0 (D) none of these

The equaiton of the line which bisects the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 (A) (4-sqrt(5))x-(3-2(sqrt(5)) y+ (2-4sqrt(5))=0 (B) (3-2sqrt(5)) x- (4-sqrt(5))y+ (2+4(sqrt(5))=0 (C) (4+sqrt(5)x-(3+2(sqrt(5))y+ (2+4(sqrt(5))=0 (D) none of these

Solve for x and ysqrt(2)x-sqrt(3)y=0,sqrt(5)x+sqrt(2)y=0