Surfaces of a thin equi-convex glass lens have radius of curvature R. Paraxial rays are incident on it . If the final image is formed after n internal reflections, calculate distance of this image from pole of the lens. Refractive index of glass is `mu`.

If the plane surface of a plano-convex lens of radius of curvature R and refractive index mu is silvered, then its focal length would be

If the plane surface of a plano-convex lens of radius of curvature R and refractive index mu is silvered, then its focal length would be

CHC The radius of curvature of each surface of an equiconvex lens is R = 42 cm. Refractive index of the glass = 1.25. If the final image forms after four internal reflections (but not TIR) inside the lens (for paraxial ray incident beam parallel to principal axis) calculate the distance of the image from the lens, in cm.

A parallel beam of light passes parallel to the principal axis and falls on one face of a thin convex lens offocal length f and after two internal reflections from the second face forms a real image. The distance of image from lens if the reflactive index of material of lens is 1.5 :

The focal length of an equi-convex lens is greater than the radius of curvature of any of the surfaces. Then, the refractive index of the material of the lens is

There is a thin double convex lens having surfaces of radius of curvature R and 2R. Lens is kept in air and refractive index of the material of the lens is mu . Focal length of the lens

Focal length of the plano-convex lens is when its radius of curvature of the surface is R and n is the refractive index of the lens.

An object is at a distance of d=2.5 cm from the surface of a glass sphere with a radius R=10 cm. Find the position of the final image produced by the sphere. The refractive index of glass is mu_1.5.