325325 is a six-digit number. It is divisible by 7 only  (b) 11 only  (c) 13 only   (d) all 7, 11 and 13

A 6-digit number is formed by repeating a 3-digit number: for example, 256256 or 678678 etc. Any number of this form is always exactly divisible by 7 only (b) 11 only (c) 13 only (d) 1001

If the 6-digit number 479xy9 is divisible by each of 7,11,13, then (x-y) is equal to -

6897 is divisible by 11 only (c) both 11 and 19 (d) neither 11 nor 19

If the six-digit number 479 xyz is exactly divisible by 7, 11 and 13, then {( y + z) :x} is equal to :

111,111,111,111 is divisible by (a)3 and 37 only (b)3,11 and 37 only (c)3,11,37 and 111 only quad (d) 3,11,37,111 and 1001

A 4 -digit number is formed by repeating a 2- digit number such as 2525,3232 etc.Any number of this form is exactly divisible by 7 (b) 11 (c) 13 (d) Smallest 3-digit prime number

A 3 -digit number 4a3 is added to another 3- digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then (a+b) is (a) 10 (b) 11 (c) 12 (d) 15

Which among the given numbers are exactly divisible by 7, 11 and 13?

Which among the following numbers is exactly divisible by 7,11 and 13 ?

If a six digit number is formed by repeating a three digit no (eg. 214214,656656) then resultant number will be divisible by only 7 only 13 only 11 1001