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The line (k + 1)x + ky-2k^2-2=0 passes t...

The line `(k + 1)x + ky-2k^2-2=0` passes through a point regardless of the value k. Which of the following is the line with slope 2 passing through the point?

Text Solution

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the line given is `(k+1)^2x +ky-2k^2 -2 = 0`
as `y=mx+c`
`ky= -(k+1)^2x+ (2k^2+2)`
`y= -(k+1)^2x/k + (2k^2+2)/k`
where `m= -(k+1)^2/k = 2`
`-(k+1)^2 = 2k`
`-(k^2+2k+1) = 2k`
`-k^2 -2k-2k-2=0`
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