Consider the differential equation `y^2dx+(x-1/y)dy=0` if `y(1)=1` then `x` is

Consider the differential equation y^(2)dx+(x-(1)/(y))dy=0 if y(1)=1 then x is

Consider the differential equation y^(2)dx+(x+(1)/(y))dy=0. If y(1)=1, then x is given by: (A) 1-(1)/(y)+((1)/(e^(j)))/(e)(B)4-(2)/(y)-(e^(y))/(e)(C)3-(1)/(y)+(e^(y))/(e)(D)1+(1)/(y)-((1)/(e^(y)))/(e)

Consider the differential equation, y^(2)dx+(x-1/y)dy=0. If value of y is 1 when x = 1, then the value of x for which y = 2, is

Consider the differential equation y^2 + (x - 1/y) (dy)/(dx) = 0 Solve the given differential equation

Consider the differential equation ydx-(x+y^(2))dy=0 . If for y=1, x takes value 1, then value of x when y = 4, is

Consider the differential equation ydx-(x+y^(2))dy=0 . If for y=1, x takes value 1, then value of x when y = 4, is

Consider the differential equation y^2 + (x - 1/y) (dy)/(dx) = 0 Find (dx)/(dy)

Solve the differential equation (x+y)dy+(x-y)dx=0; given that y=1 when x=1.

Solve the differential equation : (1-x^2)(1-y)\ dx=x y(1+y)dy