In the given figure, PA, QB and RC each is perpendicular to AC such that `PA=x, RC=y, QB=z, AB=a, and BC=b`
Prove that `(1)/(x)+(1)/(y)=(1)/(z)`

In the given figure, each of PA, QB and RC is perpendicular to Ac. If AP=x,QB=z, RC=y, AB=a and BC=b , show that (1)/(x)+(1)/(y)=(1)/(z)

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

AB, CD, PQ are perpendicular to BD. If AB = x, CD = y and PQ = z prove that (1)/(x) + (1)/(y) = (1)/(z)

If a^(x)=b^(y)=c^(z) and b^(2)=ac prove that (1)/(x)+(1)/(z)=(2)/(y)

In the above figure, seg PA, seg QB and seg RC are perpendicular to seg AC. From the information given in the figure, prove that: (1)/(x) + (1)/(z) = (1)/(y)

a^(x)=b^(y)=c^(z) and b^(2)=ac then prove that (1)/(x)+(1)/(z)=(2)/(y)

In the following figure, AB, CD and EF are perpendicular to the straight line BDF. If AB = x and, CD = z unit and EF = y unit, prove that : 1/x + 1/y = 1/z

In the given figure AB|PQ|CD, AB =x units ,CD=y units and PQ=z units,Prove that (1)/(x)+(1)/(y)=(1)/(z)