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1/(6!)+1/(7!)=x/(8!),f i n dx...

`1/(6!)+1/(7!)=x/(8!),f i n dx`

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1/(6i)+1/(7i)=x/(8i)

if 1/(6!)+1/(7!)=x/(8!) , then x is ……

y=tan^(- 1)sqrt((1-x)/(1+x))f i n d(dy)/(dx)

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f'(dx)/((x+6)^(8//7)(x-8)^(6//7)) is equal to

f(x)>0AAx in Ra n di sbou n d e ddotIf (lim)_(nvecoo)[int_0^a(f(x)dx)/(f(x)+f(a-x))+a^2+aint_a^(2a)(f(x)dx)/(f(x)+f(3a-x))+int_(2a)^(3a) (f(x)dx)/(f(x)+f(5a-x))++a^(n-1)int_((n-1)a)^(n a)(f(x)dx)/(f(x)+f[2n-1)a-x])]=7//5 (where a<1), then a is equal to 2/7 (b) 1/7 (c) (14)/(19) (d) 9/(14)

f(x)>0AAx in Ra n di sbou n d e ddotIf (lim)_(nvecoo)[int_0^a(f(x)dx)/(f(x)+f(a-x))+a^2+aint_a^(2a)(f(x)dx)/(f(x)+f(3a-x))+int_(2a)^(3a)(f(x)dx)/(f(x)+f(5a-x))++a^(n-1)int_((n-1)a)^(n a)(f(x)dx)/(f(x)+f[2n-1)a-x])]=7//5 (where a<1), then a is equal to 2/7 (b) 1/7 (c) (14)/(19) (d) 9/(14)

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