`1.0 g`of a non-electrolyte solute (molar mass`250gmol^(-1)` was dissolved in 51.2 g of benzene. If the freezing point depression constant of benzene is `5.12K kgmol^(-1)` the lowering in freezing point will be

1.0 g of a non-electrolyte solute (molar mass 250 g "mol"^(-1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant of benzene is 5.12 K kg "mol"^(-1) , the lowering in freezing point will be

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

1.00 g of a non electrolyte solute ( molar mass 250 " g mol"^(-1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant, K_(f) of benzene is 5*12 K kg "mol"^(-1) , the freezing point of benzene will be lowered by

1.0 g of a non-electrolyte solute( mol. Mass 250.0 g mol^(-1) ) was dissolved in 5.12 g benzene. If the freezing point depression constant, K_(f) of benzene is 5.12 K kg mol^(-1) , the freezing point of benzene will be lowered by: