`S o l v e f o rx:(x+1)/(x-1)+(x-2)/(x+2)=4-(2x+3)/(x-2); x!=1,-2, 2`

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4

Let f(x) = log_(e) x and g(x) =(x^(4) -2x^(3) + 3x^(2) - 2x+2)/(2x^(2) - 2x + 1) Then , the domain of fog (x) is

f(x)=(e^(2x)-1)/(e^(2x)+1) is

f(x) = ((e^(2x)-1)/(e^(2x)+1)) is

f(x)=((e^(2x)-1)/(e^(2x)+1)) is

L e tf(x)={(x^4-5x^2+4)/(|(x-1)(x-2)6),x!=1,2 12,x=2x=1 then f(x) is continuous on the set R (b) R-[1] (c) R-[2] (d) R-[1,2]

If f_1(x)=(1)/(x), f_(2) (x)=1-x, f_(3) (x)=1/(1-x) then find J(x) such that f_(2) o J o f_(1) (x)=f_(3) (x) (a) f_(1) (x) (b) (1)/(x) f_(3) (x) (c) f_(3) (x) (d) f_(2) (x)

If the function f (x)=- 4e^((1-x)/(2))+1+x+(x ^(2))/(2)+ (x ^(3))/(3) and g (x) =f ^(-1) (x), then the vlue of g'((-7)/(6)) equals to :