If side BC of triangle ABC is produced to P and CE is drawn perpendicular on AC such that angle A: angle B: angle `C = 3:2:1`, find angle `ECD`

In the given figure, ABC is a triangle in which BC is produced to D. If angle A : angle B : angle C :: 3 : 2 : 1 and AC bot CE , then angle ECD is :

In Delta ABC , angle C = 90 ^(@) , AB = 20 and BC = 12 . D is a point in side AC such that CD = 9 Taking angle BDC = x, find sin angle ABC

In Delta ABC, if angle A : angle B : angle C = 1 : 2 : 3 , then what is BC : CA : AB ?

Internal bisector of an angle angle A of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent the sides of DABC then

In the figure, ABC is an isosceles triangle with CA=CB and BC is produced to a point D. If CE bot BC , such that angle D = (1)/(2) angle E =(1)/(2) angle A , then measure of angle ACD is

The side BC of Delta ABC is produced to D. The bisectors of angle ABC and angle ABD meet at E. If AB = AC and angle BEC = 24 ^(@). then the measure of angle ABC is :

In a Delta ABC , BC is produced to D such that CD=AC is angle BAD=111^(@), angle ACB =80^(@) . Find angle ABC= ?