The `P.E.` of an oscillation particle at rest position is `15J` and its average `K.E.` is `52J`. The total energy of particle at any instant will be-

The P.E. of an oscillation particle at rest position is 10J and its average K.E. is 5J . The total energy of particle at any instant will be-

The P.E. of an oscillation particle at rest position is 10J and its average K.E. is 5J . The total energy of particle at any instant will be-

The P.E. of an oscillation particle at rest position is 10J and its average K.E. is 5J . The total energy of particle at any instant will be-

Find the total energy of a particle in SHM at any instant

A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

The P.E. of a linear harmonic oscillator is 4J, when its displacment is equal to half its amplitude. The total energy of the particle is

The potential energy of a particle performing S.H.M. in its rest position is 15 J. If the average kinetic energy is 5 J, then the total energy of the particle performing S.H.M. will be

The potential energy of a particle executing SHM in its rest position is 15 J . The average kinetic energy of the particle during one oscillation is 5 J . The total energy of the particle is