Home
Class 11
MATHS
[" Coordinates of the vertices "B" and "...

[" Coordinates of the vertices "B" and "C" of a triangle "ABC" are "(2,0)" and "(8,0)" respectively.The vertex "A],[" is varying in such "a" way that "4tan(B)/(2)tan(C)/(2)=1." Then locus of Ais "((x-5)^(2))/(25)+(y^(2))/(k^(2))=1," find "k]

Promotional Banner

Similar Questions

Explore conceptually related problems

Coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0) respectively.The vertex A is varying in such a way that 4tan((B)/(2))tan((C)/(2))=1 and locus of A is "((x-5)^(2))/(25)+(y^(2))/(k^(2))=1 ,then k=

The coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0), respectively.Vertex A is moving in such a way that 4tan(3)/(2)tan(C)/(2)=1. Then find the locus of A

The coordinates of the vertices Ba n dC of a triangle A B C are (2, 0) and (8, 0), respectively. Vertex A is moving in such a way that 4tan(B/2)tan(C/2)=1. Then find the locus of A

The coordinates of the vertices Ba n dC of a triangle A B C are (2, 0) and (8, 0), respectively. Vertex A is moving in such a way that 4tanB/2tanC/2=1. Then find the locus of A

The coordinates of the vertices Ba n dC of a triangle A B C are (2, 0) and (8, 0), respectively. Vertex A is moving in such a way that 4tanB/2tanC/2=1. Then find the locus of A

The coordinates of the vertices Ba n dC of a triangle A B C are (2, 0) and (8, 0), respectively. Vertex A is moving in such a way that 4tanB/2tanC/2=1. Then find the locus of A

Coordinates of the vertices B and C of DeltaABC are (2, 0) and (8, 0) respectively. The vertex is hanging in such a way that 4 tan B/2.tan C/2 = 1 . Then the locus of A is (A) (x-5)^2/25 + y^2/9 = 1 (B) (x-5)^2/25 + y^2/16 = 1 (C) (c-5)^2/16 + y^2/25 = 1 (D) none of these

If the vertices A,B,C of a triangle ABC are (1,2,3),(-1,0,0),(0,1,2)respectively,then find /_ABC.

B and C are the vertex of a triangle ABC with coordinate (2 , 0) and (8 , 0) respectively. Another vertex A moves in such a way that it satisfies the relation 4 " tan" (B)/(2) "tan" (C)/(2) = 1 . If the equation of locus of A is (x - 5)^(2)/5^2+ (y^(2))/(k^(2)) = 1 , then the value fo k is _

If the vertices A,B, C of a triangle ABC are (1,2,3),(-1, 0,0), (0, 1,2), respectively, then find angle ABC .