int(d theta)/(b cos theta+c sin theta)d pi

int (sin theta + cos theta) * d theta

If : sin^(2) ((pi)/(4) + (theta)/(2)) - cos^(2) ((pi)/(4) + (theta)/(2))= A) sin theta B) cos theta C) sin 2 theta D) cos 2 theta

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

int_(0)^((pi)/(2))(cos theta-sin theta)/((1+cos theta)(1+sin theta))d theta equals -

int(d theta)/(sin theta cos^(3)theta) is equal to

int_(0)^(2pi) (sin 2 theta)/(a-b cos 2 theta )d theta =

int (1 + cos theta) / (theta + sin theta) d theta

int e^(tan theta)(sec theta-sin theta)d theta is equal to: (A)-e^(tan theta)sin theta+c(B)e^(tan theta)sin theta+c(C)-e^(tan theta)sec theta+c(D)e^(tan theta)cos theta+c