Let `ABC` be a triangle. If `P` is a point such that `AP` divides `BC` in the ratio `2: 3, BP` divides `CA` in the ratio `3 : 5` then the ratio in which CP divides AB is

Divide ₹ 1664 in the ratio of 5 : 3.

A(x_(1),y_(1)), B(x_(2),y_(2)), C(x_(3),y_(3)) are three vertices of a triangle ABC. lx +my +n = 0 is an equation of the line L. If P divides BC in the ratio 2:1 and Q divides CA in the ratio 1:3 then R divides AB in the ratio (P,Q,R are the points as in problem 1)

A(x_(1),y_(1)), B(x_(2),y_(2)), C(x_(3),y_(3)) are three vertices of a triangle ABC. lx +my +n = 0 is an equation of the line L. If P divides BC in the ratio 2:1 and Q divides CA in the ratio 1:3 then R divides AB in the ratio (P,Q,R are the points as in problem 1)

A(x_(1),y_(1)), B(x_(2),y_(2)), C(x_(3),y_(3)) are three vertices of a triangle ABC. lx +my +n = 0 is an equation of the line L. If P divides BC in the ratio 2:1 and Q divides CA in the ratio 1:3 then R divides AB in the ratio (P,Q,R are the points as in problem 1)

If the point A, B, C, D are collinear asnd C, D divide AB in the ratios 2:3, -2:3 respectively, then the ratio in which AS divides CD is

In figure, in what ratio, P divides AB internally.

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then