(dy)/(dx)=y tan x;y=1" when "x=0

Solve (dy)/(dx)=y tan x, " given that " y=1 " when " x=0.

Find the particular solution of the differential equation satisfying the given conditions: (dy)/(dx)=y tan x, given that y=1 when x=0

(dy)/(dx) -y =e^(x ) " when" x=0 and y=1

(dy)/(dx)=1+x tan(y-x)

Find the particular solution of (x-y)(dx+dy)=dx-dy, given y=1, when x=0

Find the particular solution of the following : (dy)/(dx)= y tan x , given that y=1 when x=0 .

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

Solve (dy)/(dx) =y^(2)tan 2x, " given that " y =2 " when " x =0 .

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to: