`R` is the set of real numbers, If `f : R -> R` is defined by `f(x) = sqrtx` then `f` is

R is the set of real numbers,If f:R rarr R is defined by f(x)=sqrt(x) then f is

Let R be the set of real numbers. If f:R->R is a function defined by f(x)=x^2, then f is (a) injective but not surjective (b) surjective but not injective (c) bijective (d) non of these

Let R be the set of real numbers. If f:R->R is a function defined by f(x)=x^2, then f is (a) injective but not surjective (b) surjective but not injective (c) bijective (d) none of these

If f:R to R is defined by f(x)=|x|, then

If f:R to R is defined by f(x)=|x|, then

Let R be set of real numbers. If f:R->R is defined by f(x)=e^x, then f is: (a) surjective but not injective (b) injective but not surjective (c) bijective (d) neither surjective nor injective.

If R is the set of real numbers and a function f: R to R is defined as f(x)=x^(2), x in R , then prove that f is many-one into function.

If R is the set of all real numbers and if f: R -[2] to R is defined by f(x)=(2+x)/(2-x) for x in R-{2} , then the range of is: