[" 12."3x-(y+7)/(11)+2=10],[2y+(x+11)/(7)=10]

3x-(y+7)/(11)+2=10 and 2y+(x+11)/(7)=10

Solve: 3x - (y+7)/11+2 =10 and 2y+ (x+11)/7 =10

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

x-y=0.9; 11/(2(x+y))=10.5

x-y=0.9; 11/(2(x+y))=10.5

Add the algebraic expressions: (11)/2x y+(12)/5y+(13)/7x ,\ -(11)/2y-(12)/5x-13\ x y

Solve by the method of elimination 2x-y=3,3x +y=7 (ii) x-y=5, 3x+ 2y = 25 (iii) (x)/(10 ) +(y)/(5) =14 ,(x)/( 8) + (y)/( 6) =15 (iv) 3(2x+y) =7xy,3 (x+3y ) =11xy (v) (4)/(x) +5y =7,(3)/(x) +4y =5 (vi) 13x +11y = 70,11x +13y =74

If one end of a diameter of the circle x^2 + y^2 - 8x - 14y+c=0 is the point (-3, 2) , then its other end is the point. (A) (5, 7) (B) (9, 11) (C) (10, 11) (D) (11, 12)

If one end of a diameter of the circle x^2 + y^2 - 8x - 14y+c=0 is the point (-3, 2) , then its other end is the point. (A) (5, 7) (B) (9, 11) (C) (10, 11) (D) (11, 12)

(x + y - 8) /( 2 ) = ( x + 2y - 14 ) /( 3) = ( 3x + y - 12)/( 11)