4a^(2)-4b^(2)+4a+1

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

Which of the following is the factor of 4a^(2)+b^(2)-4ab+2b-4a+1?

Factorise : a-b-4a^(2) + 4b^(2)

If ((a^(2)+1)^(2))/(2a-i)=x=iy, then x^(2)+y^(2) is equal to ((a^(2)+1)^(4))/(4a^(2)+1) b.((a+1)^(2))/(4a^(2)+1) c.((a^(2)-1)^(2))/((4a^(2)-1)^(2)) d.none of these

Simplify.(4a-b)/(1-4ab)-(4a+b)/(1+4ab)-(4b(1-8a^(2)))/(16a^(2)b^(2)-1)

Find the value of the products: (4a^(2)+3b)(4a^(2)+3b)ata=1,b=2