[" 54.The angle between vectors "(vec A timesvec B)" and "(vec B timesvec A)],[" ( "[" (1) "," Zero "]]

vec i*(vec i timesvec i)=

(vec i timesvec j).vec k=

Solve (vec a timesvec a)*vec b

show that (vec B timesvec C)*|vec A times(vec B timesvec C)|=0

Prove that (vec B timesvec c)*[vec A times(vec B timesvec C)]=0

If the angle between two vectors vec(a) and vec(b) is zero, then :

Find the angle between two vectors vec a and vec b, if |vec a xxvec b|=vec a*vec b

Find the angle between two vectors vec a and vec b , if | vec a xx vec b|= vec a . vec b .

If vec A,vec B,vec C are three non-coplanar vectors,then (vec A*(vec B timesvec C))/((vec C timesvec A)*vec B)+(vec B*(vec A timesvec C))/(vec C*(vec A timesvec B))

cosine of an angle between the vectors (vec a+vec b) and (vec a-vec b) If |vec a|=2,|vec b|=1 and vec a^^vec b=60^(@) is