A prism of refractive index `mu_g` deviates the incident ray towards its base. If it is immersed in a transparent liquid of refractive index `mu_1` such that `mu_1 gt mu_g` then prism would

A ray of light, travelling in a medium of refractive index 'mu_, is incident at an angle i on a composite transparent plate consisting of three plates of refractive indices mu_1,mu_2 and mu_3. The ray emerges from the composite plate into a medium of refractive index mu_4, at angle x. Then,

A ray of light, travelling in a medium of refractive index mu, is incident at an angle i on a composite transparent plate consisting of three plates of refractive indices mu_1,mu_2 and mu_3. The ray emerges from the composite plate into a medium of refractive index mu_4, at angle x. Then,

A prism of refractive index mu_1 = 1.42 and prism angle 10° is arranged with another prism of refractive index mu_2 = 1.7. If this combination gives the dispersion without deviation, then what should be the prism angle of second prism?

A lens of refractive index mu becomes a lens of focal length f' when immersed in a liquid of refractive index mu '. If the focal length of the lens in air is f, prove that f' = f.(mu'(mu-1))/((mu-mu')) .

Focal length of a lens in air is f. Refractive index of the lens is mu . Focal length changes to f_(1) if lens is immersed in a liquid of refractive index (mu)/(2) and it becomes f_(2) if the lens is immersed in a liquid of refractive index 2 mu . Then

Focal length of a lens in air is f. Refractive index of the lens is mu . Focal length changes to f_(1) if lens is immersed in a liquid of refractive index (mu)/(2) and it becomes f_(2) if the lens is immersed in a liquid of refractive index 2 mu . Then

A concave lens made of a material of refractive index mu_g is immersed in a medium of refractive index mu_l , equal to and

A convex lens of refractive index mu_g is held in a reansparent medium of refractive index mu_m If course of rays is as shown in Fig., how are mu_g and mu_m related ? .