The maximum kinetic energies of photoelectrons emitted from a metal are `k_(1)` and `k_(2)` when it is irradiated with light of wavelenght `lambda_(1)` and `lambda_(2)` respectively. Find work function of the metal.

The K.E. of photoelecttron emitted from a metal are K_(1) and K_(2) ,when it is irradiated with lights of wavelength lambda_(1) and lambda_(2) respectively .The work function of metal is …..

Maximum kinetic energies of photoelectrons emitted from a metal surface when illuminated by radiations of wavelengths lamda_(1) and lamda_(2), " are " K_(1) and K_(2) , respectively. If lamda_(1) = 3 lamda_(2) , show that, K_(1) lt (K_(2))/(3)

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then