" 25.If "[(1+cos theta+i sin theta)/(sin theta+i(1+cos theta))]^(4)=cos n theta+i sin n theta" then "

([cos theta+i sin theta)/(sin theta+i cos theta))^(4)=?

((cos theta+i sin theta)/(sin theta+i cos theta))^(4)=

If ((1+cos theta+i sin theta)/(sin theta+i+i cos theta))^(4)=cos n theta+i sin n theta , then n=

If ((1 + cos theta + i sin theta ) /(i+ sin theta + i cos theta ))= cos ntheta + i sin n theta then n is equal to :

((cos theta + i sin theta) / (sin theta + i cos theta)) ^ (4) = cos8 theta + i sin8 theta

(i) |(cos theta,-sin theta),(sin theta,cos theta)|

(cos theta + i sin theta) ^ (n) = cos n theta + i sin n theta

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta

Using De Moivre 's theorem prove that : ((1+cos theta +i sin theta)/(1+cos theta - i sin theta))^n= cos n theta + i sin n theta , where i = sqrt(-1)