For each x ER, let [x] be greatest integer less than or equal to x. Then lim (*1+1=1) sin(3) 0 is equal to: 1 O-sin 1 sin 1

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto1^+) (x([x]+absx)sin[x])/absx is equal to

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto1^+) (x([x]+absx)sin[x])/absx is equal to

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto1^+) (x([x]+absx)sin[x])/absx is equal to

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto0^-) (x([x]+absx)sin[x])/absx is equal to a) -sin1 b) 0 c) 1 d) sin 1

For each t in RR, let [t] be the greatest integer less than or equal to t. Then, lim_(x rarr 1+) ((1-|x|+sin|1-x|)sin(pi/2[1-x]))/(|1-x|[1-x])

Let [x] denote the greatest integer less than or equal to x . Then, int_(1)^(-1)[x]dx=?

For each x in R , let [x] be the greatest integer less than or equal to x, Then, lim_( x to 0^(-)) ( x ([x] + | x| ) sin [x]) / ([x]) is equal to

Let [x] denote the greatest integer less than or equal to x. If x=(sqrt3 + 1)^5, then [x] is equal to

Let [x] denote the greatest integer less than or equal to x . Then, int_(0)^(1.5)[x]dx=?