The time period of a pendulum on the surfacce of the moon is 5s. If it is a seconds pendulum on earth and the acceleratio due to gravity on the earth is `9.8 m s^(-2)`, find the acceleration due to gravity on the surface of the moon.

If g_(e) is acceleration due to gravity on earth and g_(m) is acceleration due to gravity on moon, then

If the length of a seconds pendulum on a planet is 2 m then the acceleration due to gravity on the surface of that planet is "______" (Take the acceleration due to gravity on the surface of the Earth =9.8 m s^(-2) )

A simple pendulum makes 20 oscillations in one second on the surface of the earth. Determine the time period of the simple pendulum on the surface of a planet where the acceleration due to gravity is one fourth of the acceleration due to gravity on the surface of the earth .

The period of a simple pendulum on the surface of the earth is 2s. Find its period on the surface of this moon, if the acceleration due to gravity on the moon is one-sixth that on the earth ?