Prove that the product of the perpendiculars from `(alpha,beta)` to the pair of lines `a x^2+2h x y+b y^2=0` is `(aalpha^2-2halphabeta+bbeta^2)/(sqrt((a-b)^2+4h^2))`

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines a x^2+2h x y+b y^2=0 is (aalpha^2+2halphabeta+b beta^2)/(sqrt((a-b)^2+4h^2))

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines a x^2+2h x y+b y^2=0 is (aalpha^2+2halphabeta+b beta^2)/(sqrt((a-b)^2+4h^2))

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines ax^(2)+2hxy+by^(2)=0 is (a alpha^(2)-2h alpha beta+b beta^(2))/(sqrt((a-b)^(2)+4h^(2)))

Show that the product of perpendicular from (alpha, beta) to the pair of lines ax^2 + 2hxy + by^2= 0 is |(aalpha^2 + 2h alpha beta + b beta^2)/(sqrt((a-b)^2 - (2h)^2))|

The product of the perpendiculars from (1, 1) to the pair of lines x^(2)+4 x y+3 y^(2)=0 is

The product of the perpendiculars from (-1,2) to the pair of lines 2x^(2)5xy+2y^(2)=0

The product of the perpendiculars from (-1,2) to the pair of-lines 2 x^(2)-5 x y+2 y^(2)=0 is

The product of the perpendiculars from (-1, 2) to the pair of lines 2x^(2)-5xy+2y^(2)=0

The product of the perpendiculars drawn from (2,-1) to the pair of lines x^(2)-3xy+2y^(2)=0 is