If `x` is real, then `x//(x^2-5x+9)` lies between `-1a n d-1//11` b. `1a n d-1//11` c. `1a n d1//11` d. none of these

If x is real, then x//(x^2-5x+9) =y lies between -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

If x is real, then x//(x^2-5x+9) lies between a. -1a n d-1//11 b. 1a n d-1//11 c. 1a n d1//11 d. none of these

If x is real,then x/(x^(2)-5x+9) lies between -1 and -1/11 b.1 and -1/11 c. 1and1/11d.none of these

If x is real, prove that (x)/(x^(2)-5x+9) lies between 1 and (-1)/(11) .

If x is real, show that the value of x/(x^2-5x+9) always lie between 1 and (-1/11)

if x is real,show that (x)/(x^(2)-5x+9) always lies in the interval [-(1)/(11),1]

The sum of 1+n(1-1/x)+(n(n+1))/(2!)(1-1/x)^2+oo will be a. x^n b. x^(-n) c. (1-1/x)^n d. none of these

A\ (6,3),\ B(-3,5),\ C(4,-2)\ a n d\ D(x ,3x) are four points. If Delta' D B C :'Delta'A B C=1:2, then x is equal to a. 11/8 b. 8/11 c. 3 d. none of these

A\ (6,3),\ B(-3,5),\ C(4,-2)\ a n d\ D(x ,3x) are four points. If "Delta"D B C :"Delta"A B C=1:2, then x is equal to a. 11/8 b. 8/11 c. 3 d. none of these

Slope of normal to the curve y=x^2-x at x=2 is: a) -1/3 b) -1/7 c) -1/9 d) -1/11