1 mol of `H_(2) SO_(4)` in mixed with 2 mol of `NaIH`. The heat evolved will be

For the neutralisation of 1 mol of H_(2)SO_(4) with 2 mols of NaOH in dilute solutions the heat evolved is

200 cm^(3) of 0.1 M H_(2)SO_(4) is mixed with 150 cm^(3) of 0.2M KOH. Find the value of evolved heat.

Whenever an acid is neutralised by a base, the net reaction is : H^(+)(aq) + OH^(-)(aq) to H_(2)O(l) + 57.1 kJ Calculate the heat evolved for the following experiments : (i) 0.25 mol of HCI solution is neutralised by 0.25 mol of NaOH solution. (ii) 0.60 mol of HNO_(3) solution is mixed with 0.30 mol of KOH solution. (iii) 100 cm^(3) of 0.2 M HCl is mixed with 200 cm^(3) of 0.3M NaOH. 400 cm^(3) of 0.2 M H_(2)SO_(4) is mixed with 600 cm^(3) of 0.1 M NaOH solution.

2 mol 'H_(2) is mixed with 2 gm of H_(2) . The molar heatr capacity at constant pressure for the mixture is

2 mol 'H_(2) is mixed with 2 gm of H_(2) . The molar heatr capacity at constant pressure for the mixture is

1 mol H_(2)SO_(4) will exactly neutralise :