A block of mass 1 kg slides down a rough inclined plane of inclination `60^(@)` starting from its top. If coefficient of kinetic is 0.5 and length of the plane d=2 m, then work done against friction is

A block of mass 1 kg slides down on a rough inclined plane of inclination 60^(@) starting from its top. If the coefficient of kinetic friction is 0.5 and length of the plane is 1 m , then work done against friction is (Take g=9.8m//s^(2) )

A block of mass 2 kg, slides down a rough inclined plane of length I rn and inclination 60°. The coefficient ofkinetic friction is 0.4. What is the work done against friction, when it slides from the top to the bottom?

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A block of mass m moves with constant speed down the inclined plane of inclination theta . Find the coefficient of kinetic friction.

A block of mass m moves with constant speed down the inclined plane of inclination theta . Find the coefficient of kinetic friction.

A block of mass 5 kg slides down a rough inclined surface. The angle of inclination is 45^(@) . The coefficient of sliding friction is 0.20. When the block slides 10 cm, the work done on the block by force of friction is

A block of mass 5 kg slides down a rough inclined surface. The angle of inclination is 45^(@) . The coefficient of sliding friction is 0.20. When the block slides 10 cm, the work done on the block by force of friction is

A block slides down a rough inclined plane of inclination 45^(@) . If the coefficent of kinetic friction is 0.5 , find the acceleration of the sliding block . (g=10ms^(-2)) .