In the adjoining figure, ABCD is a quadrilateral. A line through D, parallel to AC, meets BC produced in P .
Prove that `ar(triangleABP)=ar("qaud. ABCD")`.

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that ar( Delta AEDF) = ar( Delta ABCDE)

ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that: ar(ACB) = ar(ACF)

ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that: ar(AEDF) = ar(ABCDE)

In the figure, ABCD is a quadrilateral. A line DP drawn parallel to diagonal AC from point D, meet BC produced at P. Prove that: are of Delta ABP = " area of " square ABCD

In the figure, ABCD is a quadrilateral. A line DP drawn parallel to diagonal AC from point D, meet BC produced at P. Prove that: are of Delta ABP = " area of " square ABCD

ABCD is a parallelogram and a line through A meets DC at P and BC (produced) at Q. Prove that ar(triangleBPC) = ar(triangleDPQ)

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar (ACB) = ar (ACF) (ii) ar (AEDF) = ar (ABCDE)

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar (DeltaACB) = ar (DeltaACF) (ii) ar (AEDF) = ar (ABCDE)

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar (DeltaACB) = ar (DeltaACF) (ii) ar (AEDF) = ar (ABCDE)