The solubility of `CaF_(2) (K_(sp)=3.4xx10^(-11))` in `0.1 M` solution of `NaF` would be

The solubility of CaF_(2) ( K_(sp)=3.4xx10^(-11) ) in 0.01 M solution of NaF would be:

The solubility of Agcl (K_sp=1.2xx10^(-10)) in a 0.10 M NaCl solution is :

Solubility of Ag_(2)CrO_(4) ( K_(sp)=4xx10^(-13) ) in 0.1 M K_(2)CrO_(4) solution will be :

The precipitate of CaF_(2) (K_(sp)=1.7xx10^(-10)) is obtained when equal volumes of the following are mixed

The precipitate of CaF_(2) (K_(sp)=1.7xx10^(-10)) is obtained when equal volumes of the following are mixed

At 25^(@)C , solublity product of CaF_(2) is 4xx10^(-11) . Determine the solubility of CaF_(2) in its saturated solution and also the molar concentrations of the constituent ions.

The precipitate of CaF_(2) (K_(sp) = 1.7 xx 10^(-10) ) is obtained when equal volumes of the following are mixed ?

The solubility product of MgF_(2) is 7.4xx10^(-11) . Calculate the solubility of MgF_(2) in 0.1 M NaF solution