Let `f(x)=x^(2)-ax+b`, `'a'` is odd positive integar and the roots of the equation `f(x)=0` are two distinct prime numbers. If `a+b=35`, then the value of `f(10)=`

Let f(x)=x^2-ax + b, where a is an odd positive integer and the roots of the equation f(x) = 0 are two distinct prime numbers. If a + b = 35 then, the value of ([f(0)+f(2)+f(3)+...+f(10)] xx f(10))/440=0........

Let f (x) =x ^(2)-bx+c,b is an odd positive integer. Given that f (x)=0 has two prime numbers an roots and b+c =35. If the least value of f (x) AA x in R is lamda, then |(lamda)/(3)| is equal to (where [.] denotes greatest integer functio)

If f(x)=x^(3)-3x+1, then the number of distinct real roots of the equation f(f(x))=0 is

Let f(x)=x^2-bx+c,b is an odd positive integer. Given that f(x)=0 has two prime numbers as roots and b+c=35. If the least value of f(x) AA x in R" is "lambda," then "[|lambda/3|] is equal to (where [.] denotes greatest integer function)

Let f(x)=x^2-bx+c,b is an odd positive integer. Given that f(x)=0 has two prime numbers as roots and b+c=35. If the least value of f(x) AA x in R" is "lambda," then "[|lambda/3|] is equal to (where [.] denotes greatest integer function)

Let f(x)=int_1^xsqrt(2-t^2)dtdot Then the real roots of the equation , x^2-f^(prime)(x)=0 are:

Let f(x)=x^(2)-bx+c, b is a odd positive integer,f(x)=0 have two prime numbers as roots and b+c=35 Then the global minimum value of f(x) is

Let f (x) = x^(2)+10x+20. Find the number of real solution of the equation f (f (f (f(x))))=0

Let f (x) = x^(2)+10x+20. Find the number of real solution of the equation f (f (f (f(x))))=0