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The maximum length of a closed pipe that would produce a just audible sound is (V_("sound") =336 m//s) :-

If the velocity of sound in air is 336 m/s. The maximum length of a closed pipe that would produce a just audible sound will be

The maximum length of a closed pipe that would produce a just audible sound is (V_("sound") =336 m//s) :-

The maximum length of a closed pipe that would produce a just audible sound is (V_("sound") =336 m//s) :-

If the velocity of sound in air is 336 m/s. The maximum length of a closed pipe that would produce a just audible sound will be

If the velocity of sound in air is 336 ms^(-1) , the maximum length of a closed pipe that would produce a just audible sound is

A cell of e.m.f. 2V and internal resistance 1.2. Omega is connected with an ammeter of resistance 0.8 Omega and two resistors of 4.5 Omega and 9 Omega as shown in the diagram below: What would be the reading on the Ammeter?

The internal resistance of a battery of e.m.f. 100 Vis 4 Omega . A voltmeter of resistance 250 Omega is used to measure the e.m.f. of the battery. What should be the minimum value of the voltmeter resistance so that the error in finding the e.m.f. of the battery may not be more than 1 percent?

A cell of e.m.f. 1.8 V and internal resistance 2 Omega is connected in series with an ammeter of resistance 0.7 Omega and a resistor of 4.5 Omega as shown in Fig. What would be the reading of the ammeter ?

The peak value of the electric field component of an electromagnetic wave is E. At a particular instant the intensity of the wave is of 0.020 W//m^(2) . If the electric field were increased to 5E what would be the intensity of the wave ?