A bubble of volume `V_(1)` is at the bottom of a pond at `15^(@)C` and 1.5 atm pressure. When it comes at the surface, it observes a pressure of 1 atm at `25^(@)C` and has volume `V_(2)`, give `((V_(2))/(V_(1)))`:

An air bubble of volume 0.21 cm^3 at the bottom of a water tank, at 5^(@)C and 3 atm pressure, rises to the surface where the temperature is 25^(@)C and pressure is 1 atm. What will be the volume of the bubble when it reaches the surface?

The volume of a gas at '27^@' C and 1 atm pressure is V. What will be the volume of gas at '127^@' C and 4 atm

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

At constant pressure the volumes of a given mass of gas at temperatures 27^(@)C and 54^(@)C are V_(1) and V_(2) respectively. The ratio (V_(1))/(V_(2)) is

A bubble of air is underwater at temperature 15^(@)C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25^(@)C and the pressure is 1.0 bar, what will happen to the volume of the bubble?

A bubble of air is underwater at temperature 15^(@)C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25^(@)C and the pressure is 1.0 bar, what will happen to the volume of the bubble ?