`8^(3.5) : 2^5`

Simplify: (3/4)^4 (8/5)^(-3/2) (32/5)^6

Simplify : (i) (5/8)^(-7)×\ (8/5)^(-5) (ii) ((-2)/3)^(-2)×\ (4/5)^(-3)

Simplify and write the answer in the exponential form : (2^5-:2^8)^5"x"\ 2^(-5) (ii) \ (-4)^3"x"\ (5)^(-3)"x"\ (-5)^(-3) (iii) 1/8"x"\ 3^(-3)

Simplify and write the answer in the exponential form : (2^5-:2^8)^5x\ 2^(-5) (ii) (-4)^3x\ (5)^(-3)x\ (-5)^(-3) 1/8x\ 3^(-3)

In the sequence given below the sum of the two digits which immediately precede the digit '3' exceeds the sum of the two digits which immediately follow the digit '3' exceeds the sum of the two digits which immediately follow the digit '3' and sum of the two digits which immediately follow the digit '5' and sum of the two digits which immediately follow the digit '5' exceeds the sum of two digits which immediately precede the digit '5'. How many such 3's and 5's together are there ? 3 3 5 6 5 5 3 7 7 8 9 9 3 3 5 6 7 5 3 5 1 3 5 5 3 2 8 3 5 1) 5 2) 6 3) 7 4) 8 5) None of these

If 3+5-8=0 then 3^(3)+5^3-8^(3) is:

Simplify (i) {(1/3)^(-2) - (1/2)^(-3)} -: (1/4)^(-2). (ii) (5/8)^(-7) xx (8/5)^(-5).

8/5 div 2/3