If in the expansion of `(a-2b)^n ,` the sum of 5th and 6th terms is 0, then the values of `a//b=` `(n-4)/5` b. `(2(n-4))/5` c. `5/(n-4)` d. `5/(2(n-4))`

If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then th e values of a//b =

If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then th e values of a//b =

If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then the values of a/b is

If in the expansion of (a-2b)^n , the sum of 5th and 6th terms is 0, then the values of a/b a. (n-4)/5 b. (2(n-4))/5 c. 5/(n-4) d. 5/(2(n-4))

If in the expansion of (a-2b)^(n) ,the sum of 5th and 6 th terms is 0, then the values of a/b=(n-4)/(5) b.(2(n-4))/(5) c.(5)/(n-4) d.(5)/(2(n-4))

If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then the values of a/b is (a) (n-4)/(5) (b) (2(n-4))/(5) (c) (5)/(n-4) (d) (5)/(2(n-4))

In the binomial expansion of (a-b)^n, n ge 5 , the sum of 5th and 6th terms is zero, then

In the binomial expansion of (a - b)^n , n ge 5 the sum of the 5th and 6th term is zero , then find a/b

In the binomial expansion of (a - b)^n , n ge 5 the sum of the 5th and 6th term is zero , then find a/b

In the binomial expansion of (a-b)^(n),nge5, the sum of 5th and 6th terms is zero then a/b equals: