Home
Class 9
MATHS
AB of Delta ABC is produced to D. CE, th...

AB of `Delta ABC` is produced to `D. CE`, the bisector of angle ACB, meets AB at E. show that `angle CED = (angle CAB + angle CBD) / 2`

Promotional Banner

Similar Questions

Explore conceptually related problems

AB of Delta ABC is produced to D.CE, the bisector of angle ACB,meets AB at E .show that /_CED=(/_CAB+/_CBD)/(2)

The side BC of Delta ABC is produced to D. The bisectors of angle ABC and angle ABD meet at E. If AB = AC and angle BEC = 24 ^(@). then the measure of angle ABC is :

In triangle ABC, AB = AC and the bisector of angle A lt intersects BC at D. Prove that, ( 1 ) triangle ADB = triangle ADC ( 2 ) angle ABC = angle ACB

The internal bisector of angle A of Delta ABC meets BC at D and the external bisector of angle A meets BC produced at E. Prove that (BD)/(BE) = (CD)/(CE) .

In the given I is the incentre of triangle ABC. AI produced meets the circumcircle of triangle ABC at point D. Given that angle ABC = 48^(@) and angle ACB = 72^(@), calculate: angle CBD

The sides AB and AC of triangle ABC are produced to points D and E, respectiely. The bisectors of angleCBD " and " angleBCE meet at P. If angle A = 82^(@) , then the measure of angle P is :

The sides AB and AC of triangle ABC are produced to points D and E, respectively. The bisectors of angle CBD and angle BCE meet at P. If angle A = 72^@ , then the measure of angle P is : एक त्रिभुज ABC की भुजाएं AB और AC को क्रमशः बिंदु D तथा E तक बढ़ाया जाता है | angle CBD तथा angle BCE के समद्विभाजक P पर मिलते हैं | यदि angle A = 72^@ है, तो कोण P का मान ज्ञात करें

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

In the given I is the incentre of triangle ABC. AI produced meets the circumcircle of triangle ABC at point D. Given that angle ABC = 48^(@) and angle ACB = 72^(@), calculate: angle BCD