An object moving with a speed of `6.25 m//s`, is deceleration at a rate given by :
`(dv)/(dt) = -25 sqrt(v)` ,
where `v` is instantaneous speed. The time taken by the obeject, to come to rest, would be :

An object , moving with a speed of 6.25 m//s , is decelerated at a rate given by : (dv)/(dt) = - 2.5 sqrt (v) where v is the instantaneous speed . The time taken by the object , to come to rest , would be :

An object , moving with a speed of 6.25 m//s , is decelerated at a rate given by : (dv)/(dt) = - 2.5 sqrt (v) where v is the instantaneous speed . The time taken by the object , to come to rest , would be :

An object moving with a speed of 6.25 m/s , is decelerated at a rate given by: (dv)/(dt)= -2.5sqrt(v) where v is the instantaneous speed The time taken by the object to come to rest would be:

An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dv/dt=-2.5sqrt v where v is the instantaneous speed. The time taken by the object, to come to rest, would be

An object moving with a speed of 6.25 "m.s"^(-1) is decelerated at a rate given by: (dv)/(dt) = -2.5 sqrt(v) where v is the instantaneous speed. What would be the time taken by the object to come to rest?

An object moving with a speed of 6.25m/s , is decreased at a rate given by (dv/dt)=-2.5sqrt(v) where v is instantaneous speed, The time taken by the object to come to rest, would be

An object is subjected to retardation, (dv)/(dt)=-5sqrtv , which has initial velocity of 4ms^(-1) . The time taken by the object to come to rest would be