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Let M=10^[10^[10^10].If M ends with N ze...

Let `M=10^[10^[10^10]`.If M ends with N zeroes and N ends with P zeroes.The number of digits in P are:

Text Solution

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`M =10^(10^(10^10))`
We know, `10^a` will always have `a` zeroes.
`:. N = (10^(10^10))`
Similarly,`P = 10^10=10000000000`
So, `P` has `11` digits.
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