(2+i)x^(2)-(5-i)x+2(1-i)=0

Solve the equation: x^(2)-(5+i)x+(18-i)=0

Solve the equation : x^(2)-(5-i)x+(18+i)=0

Solve x^2-(5+i)x+(18-i)=0

Let A={a in R} the equation (1+2i)x^(3)-2(3+i)x^(2)+(5-4i)x+a^(2)=0 has at least one real root.Then the value of (sum a^(2))/(2) is

The root of the equation 2(1+i)x^(2)-4(2-i)x-5-3i=0, where i=sqrt(-1), which has greater modulus is

Solve: (2+i)x^2+(i+5)x-2(i-1)=0

If one root of x^(2)-(3+2i)x+(1+3i)=0 is 1+i then the other root is

If one root of x^(2)-(3+2i)x+(1+3i)=0 is 1+i then the other root is A) 1-i B) 2+i C) 3+i D) 1+3i

The roots of 2(1+i)x^2-4(2-i)x-5-3i=0 are-