[" Find the acceleration of the block of mass "M" in the "],[" situation of figure "(6-E10)." The coefficient of friction "],[" between the two blocks is "mu_(1)" and that between the bigger "],[" block and the ground is "mu_(2)" ."]

Find the acceleration of the block of mass M in the situation of figure. The coefficient of friction between the two blocks is mu_1 and that between the bigger block and the ground is mu_2 .

The block of mass M and are arrenged as the situation in fig is shown.The coefficient of friction between two block is mu and that between the bigger block and the ground is mu find the acceleration of the block

The block of mass M and are arrenged as the situation in fig is shown.The coefficient of friction between two block is mu and that between the bigger block and the ground is mu find the acceleration of the block

A small block of mass m is projected on a larger block of mass 10 m and length l with a velocity v as shown in the figure. The coefficient of friction between the two block is mu_(2) while that between the lower block and the ground is mu_(1) . Given that mu_(2) gt 11 mu_(1) . (a) Find the minimum value of v , such that the mass m falls off the block of mass 10 m . (b) If v has minimum value, find the time taken by block m to do so.

A small block of mass m is projected on a larger block of mass 10 m and length l with a velocity v as shown in the figure. The coefficient of friction between the two block is mu_(2) while that between the lower block and the ground is mu_(1) . Given that mu_(2) gt 11 mu_(1) . (a) Find the minimum value of v , such that the mass m falls off the block of mass 10 m . (b) If v has minimum value, find the time taken by block m to do so.

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

Consider the situation as shown in the figgure. The coefficent of friction between the blocks is mu . Find the acceleration of each block.

A block of mass m_(2) is placed on a horizontal table and another block of mass m_(1) is placed on top is it. An increasing horizontal force F = alpha t is exerted on the upper block but the lowwer block never moves as a result. If the coefficient of friction between the blocks is mu_(1) coefficient of friction between the blocks is mu_(1) and that between the lower block and the table is mu_(2), then what is the maximum possible value of mu_(1)//mu_(2) ?