`int_- 1^2|xsinpix|dx`

Find the value of int_(-1)^(3/2)|xsinpix|dx

Find the value of int_(-1)^(3/2)|xsinpix|dx

Evaluate: int_(-1)^(3//2)|xsinpix|dx

int_(-1)^(3//2)|xsinpix|dx

Evaluate: underset(-1)overset(3//2)int |xsinpix|dx

if I=int_(-1)^2abs(xsinpix)dx then I equals

If int_(-1)^(3//2)|xsinpix|dx = (k)/(pi^(2)) , then the value of k is :

If int_(-1)^(3//2)|xsinpix|dx = (k)/(pi^(2)) , then the value of k is :

Evaluate: int_0^1|5x-3|dx (ii) int_0^pi|cosx|dx (iii) int_(-5)^5|x-2|dx (iv) int_(-1)^1e^(|x|)dx (v) int_0^2|x^2+2x-3|dx (v) int_1^4(|x-1|+|x-2|+|x-3|)dx (vi) int_(-1)^2|x^3-x|dx