If `(x_r, y_r) ; r= 1, 2, 3, 4` be the points of intersection of the parabola `y^2 = 4ax` and the circle `x^2 + y^2+ 2gx +2fy +c=0`, then

Let (x_r,y_r),r =1,2,3,4 ne the points of intersection the parabola "y^2=4ax" and the circle"x^2+y^2+2gx+2fy+c=0"prove that y_1+y_2+y_3+y_4=0

If the points of intersection of the parabola y^(2) = 4ax and the circle x^(2) + y^(2) + 2gx + 2fy + c = 0 are (x_(1), y_(1)) ,(x_(2) ,y_(2)) ,(x_(3), y_(3)) and (x_(4), y_(4)) respectively , then _

If the circle x ^(2) + y^(2) + 2gx + 2fy+ c=0 touches X-axis, then

If the circle x ^(2) + y^(2) + 2gx + 2fy+ c=0 touches X-axis, then

The number of point of intersection of the circle x^(2)+y^(2)=2ax with the parabola y^(2)=x is

The equation of the normal at P(x_(1),y_(1)) to the circle x^(2)+y^(2)+2gx+2fy+c=0 is

The parabola y^2 = 4x and the circle (x-6)^2 + y^2 = r^2 will have no common tangent if r is equal to