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[" 0.The image of the line "],[(x-1)/(3)...

[" 0.The image of the line "],[(x-1)/(3)=(y-3)/(1)=(z-4)/(-5)" in the plane "],[2x-y+z+3=0" is the line: "]

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The image of the line (x-1)/(3)=(y-3)/(1)=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1)(x+3)/(3)=(y-5)/(1)=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/(5) (3) (x-3)/(3)=(y+5)/(1)=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/(5)

The image of the line (x-2)/(2)=(y-3)/(-3)=(z-4)/(1) in the plane x+y+z=6 can be

The image of the line (x-2)/(2)=(y-3)/(-3)=(z-4)/(1) in the plane x+y+z=6 can be

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

The distance between the line (x-2)/(1)=(y-3)/(1)=(z-4)/(5) and the plane 2x+3y-z+5=0 is

Find the image of the line (x-1)/3=(y-2)/4=(z-3)/5 on the plane x-2y+z+2=0 .